Question 87924
solve each of the following for x
  *1/8=4^(6x+2)

2^-3 = 2^(2(6x+2))

-3 = 12x+4
12x = -7

x = -7/12

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  *(1/4)^x=256

2^-2x = 2^8
-2x = 8
x = -4
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  *log10x=4

Question: Does this mean log(10x) or log(base 10)x ?
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Cheers,
Stan H.