Question 1022126

Yes i have been at this for awhile and cannot figure it out it would mean a lot. Thank you
Simplify:     (3^-2)^a*(3^b)^-2a/(3^-2)^b*(9^-b)^-3a
The books answer is 3^-2a+2b-8ab but I don't know how to get there.
<pre>{{{((3^(-2))^a * (3^b)^(- 2a))/((3^-2)^b * (9^(-b))^(-3a))}}}
{{{((3^(-2a)) * (3^(- 2ab)))/((3^(- 2b)) * (9^(3ab)))}}}
{{{((3^(-2a)) * (3^(- 2ab)))/((3^(- 2b)) * (3^2)^(3ab))}}}
{{{((3^(-2a)) * (3^(- 2ab)))/((3^(- 2b)) * (3^(6ab)))}}}
{{{(3^(-2a - 2ab))/(3^(- 2b + 6ab))}}}_________{{{3^(-2a - 2ab - (- 2b + 6ab))}}}________{{{3^(-2a - 2ab + 2b - 6ab)}}}________{{{highlight(highlight_green(highlight(3^(-2a + 2b - 8ab)))))}}}