Question 1021790
<pre>There are 9C3 ways to choose the 3 digits.

Each of those choices is made up of a largest digit, 
a middle-sized digit, and a smallest digit.

There are 8 places in an 8-digit number for the digits to go.

Choose the 2 places for the largest digit to go in 8C2 ways.
That leaves 6 places for the middle-sized digit.
Choose the 3 places for the middle-sized digit to go in 6C3 ways.
That leaves 3 places for the smallest digit.
Choose the places for the smallest digits to go in 3C3 of 1 way. 
(Only 1 way, because there are only 3 places left for the 
smallest digit).

Answer: (9C3)(8C2)(6C3)(3C3) = 47040 

Edwin</pre>