Question 1021755
{{{x^3+2x^2+4x+8}}}

group these


{{{(x^3+2x^2)+(4x+8)}}}


Factor x^2 from first group and 4 from second


{{{((x^2)(x+2))+(4(x+2))}}}


Factor out x+2 from both pieces

{{{(x+2)(x^2+4)}}}


oh, P(x)={{{(x+2)(x^2+4)}}}