Question 1021745
log1 = 0. Therefore:
log(x/2)-log(x-1) = 0
log(x/2)-log(x-1) = log(1/(x-1))+log(x/2) = log(x/(2(x-1))):
log(x/(2(x-1))) = 0
Cancel logarithms by taking exp of both sides:
x/(2(x-1)) = 1
Multiply both sides by 2(x-1):
x = 2(x-1)
Expand out terms of the right hand side:
x = 2x-2
Subtract 2x from both sides:
-x = -2
Multiply both sides by -1:
x = 2
Happy learning.
J