Question 1021739


the equation with a lead coefficient of {{{1}}} whose roots are {{{x[1]=1+2i}}} and {{{x[2]=1-2i}}}:

{{{y=(x-x[1])(x-x[2])}}}

{{{y=(x-(1+2i))(x-(1-2i))}}}


{{{y=(x-1-2i)(x-1+2i)}}}

{{{y=x*x-1*x+2i*x+x(-1)-1(-1)+2i(-1)+x(-2i)-1(-2i)+2i(-2i)}}}

{{{y=x^2-x+2i*x-x+1-2i-x(2i)+(2i)-4i^2}}}

{{{y=x^2-x+cross(2i*x)-x+1-cross(2i)-cross(x(2i))+cross(2i)-4i^2}}}

{{{y=x^2-x-x+1-4(-1)}}}

{{{y=x^2-2x+1+4}}}

{{{y=x^2-2x+5}}}