Question 1021649
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Hi  
How do I find the equation of the line passing through points (1,19) and (-1,-3)
Takes two steps:
I. find slope  m ={{{(y[1] - y[2])/(x[1] - x[2] )}}}
(1,19) and 
(-1,-3   m = 22/2 = 11
II.  Use y = mx + b and P(1,19)
  y = 11x + b
  19 = (11)(1) + b  Substitute  x and y values from P(1,19)
 19-11 = b
 8 = b
Then
 y = 11x + 8   0r  Standard form:   11x-y = -8
{{{drawing(300,300,   -20,20,-20,20,  
 grid(1),
circle(1, 19,0.6),
circle(-1,-3,0.6),
graph( 300, 300, -20,20,-20,20, 0,  11x + 8))}}}