Question 1021455
{{{x<y<z}}}


{{{system(x+y+z=16,2x=z-2,x+z=11)}}}


{{{system(x+y+z=16,2x-z=0,x+z=11)}}}


First and last equations will allow for elimination method to quickly find y.

{{{(x+y+z)-(x+z)=16-11}}}
{{{highlight(y=5)}}}


A simpler system just using last two equations lets you solve for x and z.
{{{system(2x-z=0,x+z=11)}}}
Add corresponding members will eliminate z...
{{{2x-z+x+z=11}}}
{{{3x=11}}}
{{{highlight(x=11/3)}}}


YOU can finish, finding z.