Question 1021455
1.{{{A+B+C=16}}}
2.{{{2A=C-2}}}
3.{{{A+C=11}}}
Substitute 3 into 1,
{{{11+B=16}}}
{{{B=5}}}
Then from eq. 2,
{{{C=2A+2}}}
Substitute into eq. 3,
{{{A+2A+2=11}}}
{{{3A=9}}}
{{{A=3}}}
and from eq. 3,
{{{3+C=11}}}
{{{C=8}}}
3,5,8