Question 87836
Simplify:
{{{3^(-7)x^3y^6/3^8x^6y^6}}} The {{{3^(-7)}}} can be put in the denominator as {{{3^7}}} and you can cancel the {{{y^6}}}'s to leave you with:
{{{x^3/(3^8*3^7*x^6)}}} Finally, add the exponents on the 3's {{{3^8*3^7 = 3^((8+7))}}} and subtract the exponents on the x's {{{x^3/x^6 = 1/x^((6-3))}}} so that you end up with:
{{{1/(3^15*x^3)}}} ...and if you have to evaluate: {{{3^15 = 14348907}}} your answer would be:
{{{1/14348907x^3}}}