Question 1021322
3*log(6,x)=log(6,2)+log(6,32)


Inside the rendering tags,  {{{3*log(6,x)=log(6,2)+log(6,32)}}}.


{{{log(6,x^3)=log(6,2*32)}}}


{{{log(6,x^3)=log(6,2^6)}}}


{{{x^3=2^6}}}


{{{x^3=2*2*2*2*2*2}}}


{{{x^3=(2^2)(2^2)(2^2)}}}


{{{x^3=(2^2)^3}}}
Exponents the same 3 for both bases, so {{{x=4}}}.