<PRE><B>Question 1021325</B>
A insurance representative traveled 532 mi by commercial jet and then an additional 95 mi by helicopter. The rate of the jet was four times the rate of the helicopter. The entire trip took 2.4 h. Find the rate of the jet. 
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Jet DATA:
dist = 532 mi ; rate = 4x mph ; time = 532/4x hrs
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Heli DATA:
dist = 95 mi ; rate = x mph ; time = 95/x hrs
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Equations:
time + time = 2.4 hr
532/4x + 95/x = 2.4 hr
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532x + 95*4x = 2.4x*4x
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912x = 9.6x^2
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9.6x^2 - 912x = 0
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2x(4.8x - 456) = 0
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x = 456/4.8
x = 99.13 mph (Heli rate)
4x = 396.52 mph (jet rate)
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Cheers,
Stan H.
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