Question 87806
I suspect that you meant to say the square root of 50 instead of the square of 50. So you
meant for the problem to be:
.
{{{3*sqrt(2) + sqrt(50)}}}
.
Note that 50 is 25*2. So you can substitute 25*2 for 50 and the problem becomes:
.
{{{3*sqrt(2) + sqrt(25*2)}}}
.
By the rules of square roots you can split {{{sqrt(50*2)}}} into {{{sqrt(25)*sqrt(2)}}}
to convert the problem to:
.
{{{3*sqrt(2) + sqrt(25)*sqrt(2)}}}
.
But the square root of 25 is 5 and substituting 5 for the square root of 25 changes the
problem to:
.
{{{3*sqrt(2) + 5*sqrt(2)}}}
.
Then you can factor out the square root of 2 to make the problem:
.
{{{sqrt(2)*(3 + 5)}}}
.
and replace 3+5 by 8 makes it:
.
{{{sqrt(2) * 8}}}
.
and we conventionally write this as:
.
{{{8*sqrt(2)}}}
.
Hope this helps you to understand the problem and some of the steps you can take to simplify
radicals.
.
If you really meant the problem to be:
.
{{{3* sqrt(2) + 50^2}}}
.
then please post the problem again because that is a whole different problem from the
one I worked above.