Question 1021195
{{{f(x)=ax^3+bx^2+cx+d}}}
(0,-4)
{{{a(0)^3+b(0)^2+c(0)+d=-4}}}
0.{{{d=-4}}}
(-1,2)
{{{a(-1)^3+b(-1)^2+c(-1)-4=2}}}
1.{{{-a+b-c=6}}}
(1,-4)
{{{a(1)^3+b(1)^2+c(1)-4=-4}}}
2.{{{a+b+c=0}}}
(2,8)
{{{a(2)^3+b(2)^2+c(2)-4=8}}}
{{{8a+4b+2c=12}}}
3.{{{4a+2b+c=6}}}
Adding 1 and 2,
{{{-a+b-c+a+b+c=6+0}}}
{{{2b=6}}}
{{{b=3}}}
Subtracting 2 from 3,
{{{4a+2b+c-a-b-c=6-0}}}
{{{3a+b=6}}}
{{{3a+3=6}}}
{{{a=1}}}
So then,
{{{highlight(y=x^3+3x^2-4x-4)}}}