Question 1021162
Hi there,
Second point (8,1)
Line between (0,-10) and (15,10)
Find mid point of line
Formula:
x1 + x2/2, y1 + y2/2
0 + 15/2, -10 + 10/2
(7.5,0)
Distance from (8,1) to (7.5,0)
Formula:
√(x2 - x1)^2 + (y2 - y1)^2
√(7.5 - 8)^2 + (0 - 1)^2
√(-0.5)^2 + (-1)^2
√0.25 + 1
√1.25
= 1.11 units
Ex 9.
Distance from (17,0) 
to line between (-10,-20) and (30, 10)
Mid point of line:
-10 + 30/2, -20 + 10/2
20/2, -10/2
(10,-10)
Distance between (17,0) and (10,-10)
√ (10 - 17)^2 + (-10 - 0)^2
√(-7)^2 + (-10)^2
√ 49 + 100
√149
= 12.2 units.
Hope this helps :-)