Question 1021128

What are the dimensions of a rectangle whose length is 4 more than twice the width and whose perimeter is less than 7 times the width?
Please help me out with this question as I've forgotten how to set it up. Thank you.
<pre>Let width be W
Then length or L = 2W + 4
Perimeter = 2(L + W), or 2L + 2W, or 2(2W + 4) + 2W, or 4W + 8 + 2W, or 6W + 8
We then get: {{{6W + 8 < 7W}}}
6W - 7W + 8 < 0 ------- Subtracting 7W from each side
- W + 8 < 0
- W < - 8 ------ Subtracting 8 
Width, or {{{W > (- 8)/(- 1)}}}, or {{{highlight_green(W > 8)}}}

L = 2(9) + 4 ------ Substitute 9 for W
L = 18 + 4, or {{{highlight_green(matrix(1,5, L = 22, when, W, or, width = 9))}}}

If you substitute a different value for W: the width - one that's greater than 8 - the length's value will change.