Question 1020982
Tan(π/3+π/4) = {{{(tan(pi/3)+tan(pi/4))/(1-(tan(pi/3))(tan(pi/4)))}}}
= {{{(sqrt(3)+1)/(1-sqrt(3))}}}, knowing that {{{tan(pi/3) = sqrt(3)}}} and {{{tan(pi/4) = 1}}}.

Simplifying the last expression by rationalizing the denominator, we get

Tan(π/3+π/4) = {{{-2-sqrt(3)}}}