Question 1020918
This problem can not be solved
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we are given AB=AC=6cm
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The altitude of the isosceles triangle ABC is the perpendicular bisector of the base AC, let the point of intersection of the altitude and AC be D, then
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ADC is a right triangle and we know that angle ADC is 90 degrees
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The side opposite 90 degrees in a right triangle is the longest side - the hypotenuse
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side AD = radius of circle + x where x > 0, therefore we have
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AD = 9cm + x > AC = 6cm, a contradiction
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