Question 1020996
{{{f(x)=x-2}}}
{{{g(x)=x^2}}}

{{{f(g(x))}}}...in this case function {{{f(x)}}} have {{{(x)=g(x)}}} which is {{{x^2}}}
so, you have

{{{f(x^2)=x^2-2}}}

and, same here:

{{{g(f(x))=g(x-2)=(x-2)^2=x^2-4x+4}}}