Question 87741

           Let the width of the rectangle be=xcms
               the length of the rectangle(l) =2x+1  cms
               area of the rectangle=l.b=76 cms^2
                  l.b=76   i.e (2x+1).x=76  2x^2+x-76=0  
   
     since the factors cannot be found we factorise the eq'nusing the formula
    we get two values for x x=5.9 & x=-6.4
          we consider the +ve value for x  width = 5.9cms = 0.059mts
                    length = 2(5.9)+1=11.8+1 12.8 = 0.128mts