Question 1020946
I am going to borrow a strategy from the Calculus for dummies author - 

For  f(g(x)) think of 

f(x)=2x+3 as f(stuff)=2(stuff)+3 in other words, the f(stuff ) function says to take that stuff, double it and add 3.

but here, stuff=g(x)=3x+2

so f(stuff)=2(stuff)+3 just needs the substitution, stuff=3x+2 and 

f(g(x))=2(3x+2)+3 = 6x+7

Now, let's check real quick with one substitution X=1.

f(x)=2x+3
g(x)=3x+2 

g(1)=3(1)+2=5
f(5)=2(5)+3=13

f(g(1))=6x+7= 13  (check)

Now the next one needs less explaining.

 g(f(x))

g(f(x))=3(2x+3)+2= 6x+11  << don't forget to check.