Question 1020888
Let {{{ x }}} = liters of pure antifreeze to be added
{{{ 6.2 - x }}} = liters of 40.4% solution to use
{{{ .404*( 6.2 - x ) }}} = liters of pure antifreeze in 40.4% solution
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I can say:
{{{ ( x + .404*( 6.2 - x ) ) / 6.2 = .576 }}}
{{{ ( x + 2.5048 - .404x ) / 6.2 = .576 }}}
{{{ .596x + 2.5048 = .576*6.2 }}}
{{{ .596x = 3.5712 - 2.5048 }}}
{{{ .596x = 1.0664 }}}
{{{ x = 1.7893 }}}
1.789 liters of pure antifreeze is needed
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check:
{{{ ( x + .404*( 6.2 - x ) ) / 6.2 = .576 }}}
{{{ ( 1.789 + .404*( 6.2 - 1.789 ) ) / 6.2 = .576 }}}
{{{ ( 1.789 + .404*4.4107 ) / 6.2 = .576 }}}
{{{ ( 1.789 + 1.7819 ) / 6.2 = .576 }}}
{{{ 3.571 = .576*6.2 }}}
{{{ 3.571 = 3.571 }}}
OK
Hope I got it!