Question 1020857
{{{y=mx+b}}}, and you know m=3, and you have a point known.


In POINT-SLOPE form,  {{{y-k=m(x-h)}}} and you have h=1, k=0, m=3;
{{{y-0=3(x-1)}}}
{{{y=3x-3}}}---------there it is, now in slope-intercept form.



A little rearrangement will give {{{3x-y=3}}} for standard form.