Question 1018784
I'm assuming you mean,
{{{f(x)=(x^2+5)/(x+1)}}}
So then,
{{{f(x)=(x+5/x)/(1+1/x)}}}
So when x becomes large, f(x) looks like,
{{{f(x)=(x+0)/(1+0)=x}}}
{{{y=x}}}
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*[illustration cf19.JPG].