Question 1018866
{{{A=P(1+i)^n}}}
{{{15000=P(1.06)^17}}}
{{{P=15000/(1.06)^17}}}
{{{P=5570.47}}}
.
.
.
Half the number of years? You have an odd number of years.
8 years,
{{{15000=P(1.06)^8}}}
{{{P=15000/1.06^8}}}
{{{P=9411.19}}}
9 years,
{{{15000=P(1.06)^9}}}
{{{P=15000/1.06^9}}}
{{{P=8878.48}}}