Question 1018851
{{{A+B+C=15}}}
{{{A=C-1}}}
{{{B=2+C/3}}}
Substituting,
{{{C-1+2+C/3+C=15}}}
{{{(7/3)C+1=15}}}
{{{(7/3)C=14}}}
{{{C=(3/7)14}}}
{{{C=6}}}
Then,
{{{A=6-1=5}}}
and
{{{B=2+6/3=2+2=4}}}