Question 12517
Let C = the required number of lbs of cashews.
Let P = the required number of lbs of peanuts.

1) Express as a system of linear equations:

a) {{{(3.50)C + (2.00)P = 3.00(60)}}} and
b) {{{C + P = 60}}}

2) Solve: Rewrite equation b) as: {{{P = 60 - C}}} and substitute into equation a) and solve for P.

a) {{{(3.50)C + (2.00)(60 - C) = 3.00(60)}}} Simplify and solve for C.

{{{3.5C + 120 - 2C =  180}}}
{{{1.5C + 120 = 180}}}
{{{1.5C = 60}}}
{{{C = 40}}} 40 lbs of cashews are required.

{{{P = 60 - C}}}
{{{P = 60 - 40}}}
{{{P = 20}}} 20 lbs of peanuts are are required.