Question 1020362
For this biased die, assume that each of outcomes 1, 2, 3, 4, and 5 would have probability p, while 6 would have probability 5p.
We then find the value of p.
==> p+p+p+p+p+5p = 1 ==> 10p = 1 ==> p = 1/10 or 0.10
==> 6 has probability 5p = 1/2.

==>The probability it will roll 6 on the sixth roll is {{{(1/2)^5*(1/2) = 1/64 = 0.015625}}}