Question 1020349
Let {{{ x }}} = pounds of pure sodium hypochlorite
to be added
{{{ .0525*8.3 = .43575 }}} pounds of pure sodium hypochlorite
in a gallon of chlorox bleach
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{{{ ( x + .43575 ) / ( x + 8.3 ) = .07 }}}
{{{ x + .43575 = .07*( x + 8.3 ) }}}
{{{ x + .43575 = .07x + .581 }}}
{{{ .93x = .14525 }}}
{{{ x = .1562 }}}
.1562 pounds of pure sodium hypochlorite must be added
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check:
{{{ ( x + .43575 ) / ( x + 8.3 ) = .07 }}}
{{{ ( .1562 + .43575 ) / ( .1562 + 8.3 ) = .07 }}}
{{{ .592 / 8.456 = .07 }}}
{{{.070008 = .07 }}}
OK -close enough