Question 1020352

{{{4}}}{{{ 6/8}}} + {{{3}}}{{{ 2/3}}} here you have to add to mixed numbers
first what you need is to covert them to improper fractions 

{{{4}}}{{{ 6/8}}} as an improper fraction will be {{{(4*8+6)/8=38/8}}}
and {{{3}}}{{{ 2/3}}} will be {{{(3*3+2)/3=11/3}}}

now add them

{{{38/8 +11/3}}}...since we have to add improper fractions with different denominators, we need to find common denominator, the number that is divisible by both {{{8}}} and {{{3}}}, and that is {{{24}}}

{{{(38*3)/(8*3) +(11*8)/(3*8)}}}


{{{114/24 +88/24}}}...now we can add them


{{{(114 +88)/24}}}


{{{202/24}}}....now we can simplify it, divide both numerator and denominator by {{{2}}}


{{{101/12}}}....this is your solution written as an improper fraction

you can also convert it into mixed number and it will be:{{{8}}}{{{5/12}}}


or, you can do it this way (might be easier)

{{{4}}}{{{ 6/8}}} + {{{3}}}{{{ 2/3}}} first, you can write mixed numbers like this:

{{{4+ 6/8}}} and {{{3+2/3}}}...now add them


{{{4+ 6/8+3+2/3}}}...


{{{(4+3)+ (6/8+2/3)}}}


{{{7+ ((6*3)/(3*8)+(2*8)/(8*3))}}}


{{{7+ (18/24+16/24)}}}


{{{7+ (34/24)}}}...simplify


{{{7+ (17/12)}}}.........{{{17=12+5}}}, so we can write it 


{{{7+ (12/12+5/12)}}}


{{{7+ 1+5/12)}}}


{{{8+5/12)}}} or {{{8}}}{{{5/12)}}}