Question 1020205
I will assume that you meant 3x - 2y + 9 = 0.
Substituting the coordinates of the point into the equation, we get

3*1 - 2*6 + 9  =3 - 12 +9 = 0, 
and so the point (1,6) is a point on the line.

By the point-slope form {{{y - y[0] = m(x-x[0])}}}, 
==> {{{y-7 = (3/2)*(x-3)}}}, or 2y - 14 = 3x - 9
or3x-2y+5 = 0.