Question 1020125
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Please help me solve this problem: y=x^2-4x+10
                                   y=2x+10
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You are given a system of two equations

{{{y}}} = {{{x^2-4x+10}}},    (1)
{{{y}}} = {{{2x+10}}}.        (2)

Since their left sides are identical, you can equate their right sides. Then you will get an equation

{{{2x + 10}}} = {{{x^2 -4x + 10}}}.

(Notice: it is the same as to substitute expression (2) into equation (1)).

Simplify:

{{{x^2 -6x}}} = {{{0}}}.

Factor the left side polynomial. You will get

x*(x-6) = 0.

It has two roots: x=0 and x=6.
The corresponding y's are (from (2)):  y = 2x+10 = 2*0+10 = 10  and  y = 2*6+10 = 22, correspondingly.

<U>Answer</U>. There are two solutions: 1) (x,y) = (0,10)  and  2) (x,y) = (6,22).
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