Question 87707
The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle?
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Let the width be x; the length will be "x+1".
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Using Pythagoras:
diagonal^2 = x^2 + (x+1)^2

16= 2x^2 + 2x +1

2x^2+2x-15 = 0

x = [-2+-sqrt(124)]/4
Positive answer:
x = [-2+sqrt(124)]/4

x = 2.28388... (width)
x+1 = 3.28388... (length)
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Cheers,
Stan H.