Question 1020109
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sqrt{b}\ =\ b^{\frac{1}{2}}]


so


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log\left(\sqrt{7}\right)\ =\ x]


is the same as


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log\left(7^{\frac{1}{2}}\right)\ =\ x]


So


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{1}{2}\log(7)\ =\ x]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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