Question 1020098
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Perpendicular lines have NEGATIVE reciprocal slopes.  So try deriving the equation of the perpendicular through the point (-3,1) again and see if you 
don't have a better result.


As soon as you have the correct point of intersection, use the distance formula to calculate the distance between the given point and the point of 
intersection.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ d\ =\ \sqrt{(x_1\ -\ x_2)^2\ +\ (y_1\ -\ y_2)^2}]


where *[tex \Large \left(x_1,y_1\right)] and *[tex \Large \left(x_2,y_2\right)] are the coordinates of the given points.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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