Question 1019947
 
Question:
in a certain general assembly three major prizes are at stake.In how many ways can the first second and third prizes be drawn from a box.containing 120 names?
 
Solution:
Here the three prizes are distinct, so order is important.
First prize: 120 choices of names (assumed distinct).
Second prize: 119 choices.
third prize: 118 choices.
Total number of ways = product of the three = 120*119*118 = 1685040