Question 1019996
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Use the substitution method to solve the following system of equations. 
(1) 3x + 4y = 8
(2) x/4 + y/3 = 1
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3x + 4y = 8,     (1)
x/4 + y/3 = 1.   (2)

Multiply equation (2) by 3*4 = 12 (both sides). You will get

3x + 4y = 12     (3)

instead of (2).

Now you have this system of two equations

3x + 4y = 8,     (1)
3x + 4y = 12.    (3)

Their left side are identical, while right sides are different,

It means that the system has no solution.
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