Question 1019940
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If *[tex \Large a] is a zero of a polynomial function, then *[tex \Large x\ -\ a] is a factor of the polynomial.  Hence, the two factors of your quadratic polynomial are *[tex \Large (x\ -\ 3)(x\ +\ 3)].  Just multiply the two factors and collect like terms.  Hint: The product of two conjugates is the difference of two squares.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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