Question 1017344
Using the Pythagorean theorem
a^2 + b^2 = c^2
Since we have a square,
a^2 + a^2 = c^2
2a^2 = c^2
We are given the diagonal {{{2*sqrt(2)}}}
Substituting this for c
{{{2a^2 = (2*sqrt(2))^2}}}
{{{2a^2 = (4*2)}}}
divide each side by 2
{{{a^2 = (4)}}}
Take the square root of each side
a = 2