Question 1019843
You can take the log to the base {{{ 4 }}}
of both sides
{{{ ( 1/16 )^x = 4*( 64 )^x }}}
{{{ x*( -2 )  = 1 + x*3 }}}
{{{ -2x = 1 + 3x }}}
{{{ 5x = -1 }}}
{{{ x = -1/5 }}}
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check:
{{{ ( 1/16 )^(-1/5) = 4*64^(-1/5) }}}
I'll do it with calculator
{{{ .0625^(-.2) = 4*64^(-.2) }}}
{{{ 1.7411 = 4*.4353 }}}
{{{ 1.7411 = 1.7411 }}}
OK