<PRE><B>Question 1019810</B>
You can roll 36 possible outcomes
1 1
1 2
1 3 
.
.
.
6 4
6 5
6 6
Half start with an odd number. 
The remaining half that start with an even number have an odd number for the second die.
So 3/4 or 27 of those have at least one odd number.
There are 5 pair that sum to eight.
2 6
3 5
4 4 
5 3 
6 2
Two of the outcomes are both (at least one odd, sum to 8).
So,
{{{P=(27+5-2)/36=30/36=5/6}}}

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