Question 87655
Remember the law of logarithms:  {{{log (p/q) = log p - log q }}}.


Therefore, if you are given that {{{log ((p+q)) = log p- log q}}},

then replace the right side as follows:{{{log ((p+q)) = log(p/q) }}}


Take the antilog of each side and it looks like this: {{{(p+q) = (p/q)}}}

Muliply both sides by q: {{{q(p+q) = p}}}
{{{pq+ q^2 = p }}}


Subtract pq from each side:
{{{q^2 = p-pq }}}


Factor the right side:
{{{q^2 = p(1-q) }}}

{{{p(1-q)=q^2}}}


R^2  Retired from SCC