Question 1019729
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In order to have an average of 90, your total points for the 4 tests must be 5 times 90, or 450 points.  The reason you multiply by 5 is that the last test is worth double the first three, so it is the same as having 5 tests.  You know the total points of the first three tests by simply adding them.  Then subtract from 450 to know the score needed on the last one.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

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*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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