Question 87646
time to be a little sneaky then...

{{{ y^3+5y^2-9y-45 }}}
or...
{{{ y^3-9y +5y^2-45 }}}
so think about the 2 sets of terms, bracketed:
{{{ (y^3-9y) + (5y^2-45) }}}
{{{ y(y^2-9) + 5(y^2-9) }}}


and you notice that both factorised terms have a common term which can be factorised out, giving us:
{{{ (y^2-9)(y+5) }}}


The first term is a difference of 2 squares so:
{{{ (y+3)(y-3)(y+5) }}}


there you go :-)


cheers
Jon