Question 87591
    Consider an rt. angled triangle ABC with angle ACB = 90 and angle CAB = 40.
 Since his hand is 2ms high from the ground , the height of the kite is
         

           BC   = 30 sin 40 + 2
                = 30 (0.6428 ) + 2
                = 19.284 + 2
                = 21.284 m