Question 1019301
you did not specify whether this was direct or inverse variation.


the formula for direct variation would be y = kx^2.


the formula for inverse variation would be y = k/x^2.


in both cases, you solve for k first and then use that value of k to solve the rest of the problem.


you are given that y = 18 when x equals 6.


in direct variation the formula of y = kx^2 becomes 18 = k*6^2 which becomes 18 = 36k.


solve for k to get k = 18/36 = .5


now that you have k, you can make the graph.


it will look like the following:


<img src = "http://theo.x10hosting.com/2016/021203.jpg" alt="$$$" </>


in inverse variation, the formula of y = k/x^2 becomes 18 = k/6^2 which becomes 18 = k/36.


solve for k to get k = 18*36 = 648.


now that you have k, you can make the graph.


it will look like the following:



<img src = "http://theo.x10hosting.com/2016/021204.jpg" alt="$$$" </>