Question 1019322
 
Question:
A multiple choice exam consists of 12 questions, each having 5 possible answers. To pass you must answer at least 8 out of 12 correctly. What are your chances if you go into the exam without knowing a thing and have to resort to pure guessing?
 
Solution:
Binomial distribution comes to the rescue.
Probability of X success out of n trials each with a constant probability of p is given by:
P(X;n;p)={{{C(n,X)*p^X*(1-p)^(n-X)}}}
where C(n,X) is number of combinations of X objects chosen from n distinct ones.
 
Here, 
n=12,
p=1/5
cases for passing X>=8.
So
P(X>=8;12;1/5)
=Σ {{{C(12,i)*(1/5)^i*(1-1/5)^(12-i)}}} for i=8,9,10,11,12
=0.000519+0.000058+0.0000004+0.000000+0.000000
=0.000581