Question 1019261
sketch a quadrilateral EFGH. Mark in ∠GEF =50°,∠FGE=50°,
∠EGH=40° and ∠EHG=90°.  Calculate ∠EFG and ∠HEG
<pre>
{{{drawing(400,400,-.2,1.2,-.2,1.2,


line(0,.1763269807,1,0),
line(1,1.015426612,1,0),
line(1,1.015426612,0,1.015426612),
line(1,1.015426612,0,.1763269807),
line(0,.1763269807,0,1.015426612),
locate(.1,.23,"50°"),locate(.9,.9,"50°"),
locate(.8,.98,"40°"), locate(.02,.98,"90°"),
locate(0,.17,E), locate(1,0,F), locate(1,1.08,G), locate(0,1.08,H)


 )}}}

&#8736;EFG + &#8736;GEF + &#8736;FGE = 180°
&#8736;EFG +  50° +   50° = 180°
        &#8736;EFG + 100° = 180°
               &#8736;EFG = 180° - 100°
               &#8736;EFG = 80°

&#8736;HEG + &#8736;EGH + &#8736;EHG = 180°
&#8736;HEG +  40° +   90° = 180°
        &#8736;HEG + 130° = 180°
               &#8736;HEG = 180° - 130°
               &#8736;HEG = 50°

Edwin</pre>