Question 1019226
Let {{{ s }}} = one side of the square field
{{{ s^2 = 54 }}} m2
{{{ s = 7.348 }}}
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{{{ 4s }}} = the perimeter of the field
{{{ 4s = 4*7.348 }}}
{{{ 4s = 29.394 }}}
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Twice around the field is:
{{{ 2*29.394 = 58.788 }}} m