Question 1018929
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Eight less than 9 time a number is the same as the square of the number. Find the number.
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Your equation is 

{{{9x - 8}}} = {{{x^2}}}.    (1)


Simplify and solve it:

{{{x^2 - 9x + 8}}} = {{{0}}}

Factor left side:

(x-1)*(x-8) = 0,

The roots qre x = 1 and/or x = 8.

<U>Check</U>. x = 1:  9x - 8 = 1.  {{{x^2}}} = 1.  Equality (1) is valid.

        x = 8:  9x - 8 = 64.  {{{x^2}}} = 64.  Equality (1) is valid.

<U>Answer</U>. The number is 1 or 8.
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